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प्रश्न
If cos θ : sin θ = 1 : 2, then find the value of `(8costheta - 2sintheta)/(4costheta + 2sintheta`
उत्तर
cos θ : sin θ = 1 : 2
The value of `(8costheta - 2sintheta)/(4costheta + 2sintheta`
= `(8(sintheta/2) - 2sintheta)/(4(sintheta/2) + 2sintheta)`
= `(4 sintheta - 2 sintheta)/(2 sintheta + 2 sintheta)`
= `(2 sintheta)/(4 sintheta)`
= `2/4`
= `1/2`
Aliter:
cos θ : sin θ = 1 : 2
cos θ = sin θ
⇒ 2 = `sintheta/costheta`
⇒ 2 = tan θ
AC = `sqrt(1^2 + 2^2)`
= `sqrt(1 + 4)`
⇒ `sqrt(5)`
∴ sin θ = `2/sqrt(5)`, cos θ = `1/sqrt(5)`
The value of `(8 cos theta - 2 sin theta)/(4 cos theta + 2 sin theta)`
= `8(1/sqrt(5)) - 2(2/sqrt(5)) ÷ 4(1/sqrt(5)) + 2 xx (2/sqrt(5))`
= `(8/sqrt(5)) - (4/sqrt(5)) ÷ (4/sqrt(5)) + (4/sqrt(5))`
= `((8 - 4)/sqrt(5)) ÷ ((4 + 4)/sqrt(5))`
= `(4/sqrt(5)) ÷ (8/sqrt(5))`
= `(4/sqrt(5)) xx (sqrt(5)/8)`
= `(4/8)`
= `1/2`
∴ The value is `1/2`
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