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प्रश्न
In the following figure, altitudes AD and CE of ΔABC intersect each other at the point P. Show that:
ΔPDC ∼ ΔBEC
उत्तर
In ΔPDC and ΔBEC
∠PDC = ∠BEC = 90°
∠PCD = ∠BCE ...(Common angle)
Hence, by using the AA similarity criterion,
ΔPDC ∼ ΔBEC
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