मराठी

In the Given Figure, Pt Touches a Circle with Centre O at R. Diameter Sq When Produced to Meet the Tangent Pt at P. If ∠Spr = X° and ∠Qrp = Y°; Show that X° + 2y° = 90° - Mathematics

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प्रश्न

In the given figure, PT touches a circle with centre O at R. Diameter SQ when produced to meet the tangent PT at P. If ∠SPR = x° and ∠QRP = y°; Show that x° + 2y° = 90°

बेरीज

उत्तर

PRT is tangent at R and QR is a chord.
∠QRP = ∠QSR     ...(Angle is an alternate segment)
∠QRP = y°
and ∠QSR = 90°   ...( QS is diameter and angle in a semicircle is right angle)

Now, in Δ PRS,
∠SPR + ∠PRS + ∠RSP = 180°
x° + y° + 90° + y° = 180°
x° + 2y° = 180° - 90°
x° + 2y° = 90°
Hence proved.

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पाठ 15: Circles - Exercise 1

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आईसीएसई Mathematics [English] Class 10
पाठ 15 Circles
Exercise 1 | Q 12

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