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प्रश्न
Show that:
(ii) `(cos30^0+sin 60^0)/(1+sin30^0+cos60^0)=cos 30^0`
उत्तर
LHS =`(cos30^0+sin 60^0)/(1+sin30^0+cos60^0) = ((sqrt(3)/2+sqrt(3)/2))/(1+1/2+1/2)=((sqrt(3)+sqrt(3))/2)/((2+1+1)/2)=sqrt(3)/2`
Also, RHS = cos `30^0=sqrt(3)/2`
Hence, LHS = RHS
∴`(cos30^0+sin 60^0)/(1+sin30^0+cos60^0)=cos 30^0`
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