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प्रश्न
Solve for x: `("log"289)/("log"17)` = logx
उत्तर
`("log"289)/("log"17)` = logx
⇒ `("log"17^2)/("log"17)` = logx
⇒ `(2"log"17)/("log"17)` = logx
⇒ 2 = logx
⇒ 2log10 = logx ...(since log10 = 1)
⇒ log102 = logx
∴ x = 102
= 100.
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