Advertisements
Advertisements
प्रश्न
Without using trigonometric table , evaluate :
`(sin47^circ/cos43^circ)^2 - 4cos^2 45^circ + (cos43^circ/sin47^circ)^2`
उत्तर
`(sin47^circ/cos43^circ)^2 - 4cos^2 45^circ + (cos43^circ/sin47^circ)^2`
⇒ `((sin47^circ)/(cos43^circ))^2 + (cos43^circ/sin47^circ)^2 - 4(1/sqrt(2))^2`
⇒ `(sin(90^circ - 43^circ)/cos43^circ)^2 + (cos(90^circ - 47^circ)/sin47^circ)^2 - 4(1/2)`
⇒ `(cos43^circ/cos43^circ)^2 + (sin47^circ/sin47^circ)^2 - 2`
⇒ 1 + 1 - 2 = 0
APPEARS IN
संबंधित प्रश्न
Write the value of `( 1- sin ^2 theta ) sec^2 theta.`
\[\frac{1 - \sin \theta}{\cos \theta}\] is equal to
If x = a cos θ and y = b sin θ, then b2x2 + a2y2 =
Prove the following identity :
`(cosecθ)/(tanθ + cotθ) = cosθ`
Choose the correct alternative:
1 + tan2 θ = ?
Prove that `sqrt((1 - sin θ)/(1 + sin θ)) = sec θ - tan θ`.
Prove that `(sec θ - 1)/(sec θ + 1) = ((sin θ)/(1 + cos θ ))^2`
Prove that sin( 90° - θ ) sin θ cot θ = cos2θ.
Prove that: `(sin θ - 2sin^3 θ)/(2 cos^3 θ - cos θ) = tan θ`.
(sec θ + tan θ) . (sec θ – tan θ) = ?
