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Question
A batsman scores runs in 10 innings as 38, 70, 48, 34, 42, 55, 63, 46, 54 and 44. The mean deviation about mean is
Options
8.6
6.4
10.6
7.6
None of these
Solution
None of these
\[N = 10\]
\[X = \frac{38 + 70 + 48 + 34 + 42 + 55 + 63 + 46 + 54 + 44}{10} \]
\[ = \frac{494}{10}\]
\[ = 49 . 4\]
| xi | di = \[\left| x_i - 49 . 4 \right|\] |
| 34 | 15.4 |
| 38 | 11.4 |
| 42 | 7.4 |
| 44 | 5.4 |
| 46 | 3.4 |
| 48 | 1.4 |
| 54 | 4.6 |
| 55 | 5.6 |
| 63 | 13.6 |
| 70 | 20.6 |
|
\[\sum^n_{i =} d_i = 88 . 8\]
|
\[\text{ Mean deviation from the mean } = \frac{88 . 8}{10}\]
\[ = 8 . 88\]
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