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Question
A reaction is second order with respect to a reactant. How is the rate of reaction affected if the concentration of the reactant is doubled?
Solution
Rate of reaction, R = k [A]2
If the concentration of the reactant is doubled, i.e. [A] = 2R, then the rate of the reaction would be R = k(2R)2
= 4kR2
= 4 R
Therefore, the rate of the reaction would increase by 4 times.
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