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Check the injectivity and surjectivity of the following function. f : N → N given by f(x) = x3 - Mathematics and Statistics

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Question

Check the injectivity and surjectivity of the following function.

f : N → N given by f(x) = x3

Sum

Solution

f : N → N given by f(x) = x3 

Let f(x1) = f(x2)

∴ x13 = x23

∴ x13 – x23 = 0

∴ `(x_1 - x_2) underbrace((x_1^2 + x_1 x_2 + x_2^2))_(> 0  "for all"  "x"_1,  "x"_2  "as it's discriminant" < 0)` = 0

∴ x1 = x2

∴ f is injective.

Numbers from codomain which are not cubes of natural numbers are not images under f.

∴ f is not surjective.

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Chapter 6: Functions - Exercise 6.1 [Page 119]

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