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D is a Point on the Side of the Bc of δAbc. Prove that the Perimeter of δAbc is Greater than Twice of Ad. - Mathematics

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Question

D is a point on the side of the BC of ΔABC. Prove that the perimeter of ΔABC is greater than twice of AD.

Sum

Solution


Construction: Join AD
In triangle ACD,
AC + CD > AD  ...(i)
(Sum of two of a triangle greater than the third side)
Similarly, in triangle ADB,
AB + BD > AD  ...(ii)
Adding (i) and  (ii),
AC + CD + AB + BD > AD
AB + BC + AC > 2AD.   ...(Since, CD + BD = BC)

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Chapter 13: Inequalities in Triangles - Exercise 13.1

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Frank Mathematics [English] Class 9 ICSE
Chapter 13 Inequalities in Triangles
Exercise 13.1 | Q 9
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