English

Determine whether the expansion of (x2-2x)18 will contain a term containing x10? - Mathematics

Advertisements
Advertisements

Question

Determine whether the expansion of `(x^2 - 2/x)^18` will contain a term containing x10?

Sum

Solution

Let Tr+1 contain x10.

Then Tr+1 = `""^18"C"_r  (x^2)^(18 - r)  (-2^r)/x`

= `""^18"C"_r  x^(36 - 2r)  (-1)^r  * 2^r  x^(-r)`

= `(-1)^r  2^r  ""^18"C"_r  x^(36 - 3r)`

Thus, 36 – 3r = 10

i.e., r = `36/3`

Since r is a fraction, the given expansion cannot have a term containing x10.

shaalaa.com
  Is there an error in this question or solution?
Chapter 8: Binomial Theorem - Solved Examples [Page 133]

APPEARS IN

NCERT Exemplar Mathematics [English] Class 11
Chapter 8 Binomial Theorem
Solved Examples | Q 6 | Page 133

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Expand the expression (1– 2x)5


Expand the expression: `(x/3 + 1/x)^5`


Expand the expression: `(x + 1/x)^6`


Using Binomial Theorem, evaluate the following:

(96)3


Show that 9n+1 – 8n – 9 is divisible by 64, whenever n is a positive integer.


Prove that `sum_(r-0)^n 3^r  ""^nC_r = 4^n`


Find a if the coefficients of x2 and x3 in the expansion of (3 + ax)9 are equal.


If a and b are distinct integers, prove that a – b is a factor of an – bn, whenever n is a positive integer.

[Hint: write an = (a – b + b)n and expand]


Find an approximation of (0.99)5 using the first three terms of its expansion.


If n is a positive integer, prove that \[3^{3n} - 26n - 1\]  is divisible by 676.

 
 

Find the value of (1.01)10 + (1 − 0.01)10 correct to 7 places of decimal.

 

Show that  \[2^{4n + 4} - 15n - 16\]  , where n ∈  \[\mathbb{N}\]  is divisible by 225.

 
  
  

Find the rth term in the expansion of `(x + 1/x)^(2r)`


Expand the following (1 – x + x2)4 


Find the term independent of x in the expansion of `(sqrt(x)/sqrt(3) + sqrt(3)/(2x^2))^10`.


The total number of terms in the expansion of (x + a)51 – (x – a)51 after simplification is ______.


If (1 – x + x2)n = a0 + a1 x + a2 x2 + ... + a2n x2n , then a0 + a2 + a4 + ... + a2n equals ______.


Find the coefficient of x in the expansion of (1 – 3x + 7x2)(1 – x)16.


Find the coefficient of x15 in the expansion of (x – x2)10.


Find the sixth term of the expansion `(y^(1/2) + x^(1/3))^"n"`, if the binomial coefficient of the third term from the end is 45.


If the coefficient of second, third and fourth terms in the expansion of (1 + x)2n are in A.P. Show that 2n2 – 9n + 7 = 0.


In the expansion of (x + a)n if the sum of odd terms is denoted by O and the sum of even term by E. Then prove that O2 – E2 = (x2 – a2)n 


The two successive terms in the expansion of (1 + x)24 whose coefficients are in the ratio 1:4 are ______.


If the coefficients of (2r + 4)th, (r – 2)th terms in the expansion of (1 + x)18 are equal, then r is ______.


The positive integer just greater than (1 + 0.0001)10000 is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×