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Differentiate E 3 X Cos 2 X - Mathematics

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Question

Differentiate \[e^{3 x} \cos 2x\] ?

Solution

\[\text{ Let } y = e^{3x} \cos2x\]

\[\text{ Differentiate it with respect to x we get }, \]

\[\frac{d y}{d x} = \frac{d}{dx}\left( e^{3x} \cos2x \right)\]

\[ = e^{3x} \times \frac{d}{dx}\left( \cos2x \right) + \cos2x\frac{d}{dx}\left( e^{3x} \right) \left[ \text{Using product rule } \right]\]

\[ = e^{3x} \times \left( - \sin2x \right)\frac{d}{dx}\left( 2x \right) + \cos2x e^{3x} \frac{d}{dx}\left( 3x \right) \left[ \text{ Using chain rule } \right]\]

\[ = - 2 e^{3x} \sin2x + 3 e^{3x} \cos2x\]

\[ = e^{3x} \left( 3 \cos2x - 2 \sin2x \right)\]

\[So, \frac{d}{dx}\left( e^{3x} \cos2x \right) = e^{3x} \left( 3 \cos2x - 2 \sin2x \right)\]

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Chapter 11: Differentiation - Exercise 11.02 [Page 37]

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RD Sharma Mathematics [English] Class 12
Chapter 11 Differentiation
Exercise 11.02 | Q 21 | Page 37

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