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Question
Find `"dy"/"dx"` if, y = `"e"^(5"x"^2 - 2"x" + 4)`
Solution
y = `"e"^(5"x"^2 - 2"x" + 4)`
Differentiating both sides w.r.t.x, we get
`"dy"/"dx" = "d"/"dx"("e"^(5"x"^2 - 2"x" + 4))`
`= "e"^(5"x"^2 - 2"x" + 4) * "d"/"dx"(5"x"^2 - 2"x" + 4)`
`= "e"^(5"x"^2 - 2"x" + 4) * [5(2"x") - 2 + 0]`
∴ `"dy"/"dx" = (10"x" - 2)* "e"^(5"x"^2 - 2"x" + 4)`
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