English

If a circle is touching the side BC of ΔABC at P and is touching AB and AC produced at Q and R respectively (see the figure). Prove that AQ = 12 (perimeter of ΔABC). - Mathematics

Advertisements
Advertisements

Question

If a circle is touching the side BC of ΔABC at P and is touching AB and AC produced at Q and R respectively (see the figure). Prove that AQ = `1/2` (perimeter of ΔABC).

Sum

Solution

Given, circle touching the side BC of ΔABC at point P and AB, AC produced at Q and R, respectively.

We know, lengths of tangents drawn from on external point to a circle are equal.

∴ AQ = AR     ...(i)

BQ = BP      ...(ii)

CP = CR     ...(iii)

Perimeter of ΔABC = AB + BC + CA

=AB + (BP + PC) + (AR – CR)

= (AB + BP) + PC + (AQ – CP)     ...[From equations (i) and (ii)]

= (AB + BQ) + PC + (AQ – CP)    ...[From equation (ii)]

= AQ + PC + AQ – PC

= 2AQ

∴ AQ = `1/2` (perimeter of ΔABC)

shaalaa.com
  Is there an error in this question or solution?
2021-2022 (April) Basic - Outside Delhi Set 1
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×