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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 10

In ΔABC, D and E are points on the sides AB and AC respectively. For the following case show that DE || BC AB = 5.6 cm, AD = 1.4 cm, AC = 7.2 cm and AE = 1.8 cm. - Mathematics

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Question

In ΔABC, D and E are points on the sides AB and AC respectively. For the following case show that DE || BC

AB = 5.6 cm, AD = 1.4 cm, AC = 7.2 cm and AE = 1.8 cm.

Sum

Solution

Here AB = 5.6 cm, AD = 1.4 cm, BD = AB – AD

= 5.6 – 1.4

= 4.2

AC = 7.2 cm, AE = 1.8 cm, EC = AC – AE

= 7.2 – 1.8

EC = 5.4 cm

`"AD"/"DB" = 1.4/4.2 = 1/3`

`"AE"/"EC" = 1.8/5.4 = 1/3`

`"AE"/"EC" = "AD"/"DE"`

By converse of basic proportionality theorem DE || BC

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Thales Theorem and Angle Bisector Theorem
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Chapter 4: Geometry - Exercise 4.2 [Page 182]

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Samacheer Kalvi Mathematics [English] Class 10 SSLC TN Board
Chapter 4 Geometry
Exercise 4.2 | Q 3. (ii) | Page 182
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