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Question
In below figure, ∠A = ∠CED, Prove that ΔCAB ~ ΔCED. Also, find the value of x.
Solution
We have, ∠A = ∠CED
In ΔCAB and ΔCED
∠C = ∠C [Common]
∠A = ∠CED [Given]
Then, ΔCAB ~ ΔCED [By AA similarity]
`therefore"CA"/"CE"="AB"/"ED"` [Corresponding parts of similar Δ are proportional]
`rArr15/10=9/x`
`rArrx=(10xx9)/15=90/15=6 ` cm
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