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Question
In cyclic quadrilateral ABCD, ∠DAC = 27°; ∠DBA = 50° and ∠ADB = 33°. Calculate : ∠CAB.
Solution
∠DAB + ∠DCB = 180°
(Pair of opposite angles in a cyclic quadrilateral are supplementary)
`=>` 27° + ∠CAB + 83° = 180°
`=>` ∠CAB = 180° – 110° = 70°
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