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Question
In following figure.,ABCD is a cyclic quadrilateral . If ∠ BCD = 100° and ∠ ABD = 70° , find ∠ ADB.
Solution
In cyclic quadrilateral ABCD,
∠ BCD + ∠ DAB = 180° (Opposite angles of a cyclic quadrilateral)
100 + ∠ DAB = 180
∠ DAB = 80°
In Δ DAB ,
∠ DAB + ∠ ABD + ∠ BDA = 180°
80 + 70° + ∠ BDA = 180°
∠ BDA = 30°
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