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Question
In the given figure, if AB || DE, ∠BAC = 35º and ∠CDE = 53º, find ∠DCE.
Solution
AB || DE and AE is a transversal.
∠BAC = ∠CED .......(Alternate interior angles)
∴ ∠CED = 35º
In ΔCDE,
∠CDE + ∠CED + ∠DCE = 180º ............(Angle sum property of a triangle)
53º + 35º + ∠DCE = 180º
∠DCE = 180º − 88º
∠DCE = 92º
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