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Question
In the following figure, PQ and PR are tangents to the circle, with centre O. If ∠ QPR = 60° , calculate:
∠ QSR
Solution
Now arc RQ subtends ∠QOR at the centre and ∠QSR at the remaining part of the circle.
`therefore angle "QSR" = 1/2 angle "QOR"`
`=> angle "QSR" = 1/2 xx 120^circ`
⇒ ∠QSR = 60°
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