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Question
In the given figure, O is the centre of the circle, BO is the bisector of ∠ABC. Show that AB = BC.
Solution
It is given that,∠ABC is on circumference of circle BD is passing through centre.
Construction: Join A and C to form AC and extend BO to D such that BD be the perpendicular bisector of AC.
Now in \[\bigtriangleup BDA \text{ and } \bigtriangleup BDC\] we have
AD = CD (BD is the perpendicular bisector)
So ,
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