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Question
Prove that alogcb = blogca
Solution
Let x = alogcb, y = blogca
∴ log x = log [alogcb], log y = log [blogca]
∴ log x = logcb log a, log y = logca log b
∴ log x = `log"b"/log"c".log"a", logy = log"a"/log"c".log"b"`
∴ log x = log y
∴ x = y
∴ alogcb = blogca
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