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Question
Select the correct answer from the given alternatives:
If n is an odd positive integer then the value of 1 + (i)2n + (i)4n + (i)6n is :
Options
−4i
0
4i
4
Solution
0
Explanation;
1 + (i2)n + (i4)n + (i2)3n
= 1 – 1 + 1 – 1 …(n odd positive interger)
= 0
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