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(Sin 20°50' + Tan 67°40')/(Cos 32°20' - Sin 15°10') - Mathematics

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Question

`(sin 20°50' + tan 67°40')/(cos 32°20' - sin 15°10')`

Sum

Solution

`(sin 20°50' + tan 67°40')/(cos 32°20' - sin 15°10')`

= `(0.3557 + 2.4340)/(0.8450 - 2.616)`

= `(2.7897)/(0.5834)`

= `(27897)/(5834)`

= 4.7818.

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Chapter 18: Trigonometry - Exercise 1

APPEARS IN

ICSE Mathematics [English] Class 10
Chapter 18 Trigonometry
Exercise 1 | Q 13.2

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