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Question
The conductivity of 0.02M AgNO3 at 25°C is 2.428 x 10-3 Ω-1 cm-1. What is its molar
conductivity?
Solution
Given: C = 0.02 M , k = 2.428 x 10-3Ω-1 cm-1
To find: Molar conductivity
Formula: Molar conductivity = `(1000k)/C`
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