English

The domain and range of real function f defined by f(x) = x-1 is given by ______. - Mathematics

Advertisements
Advertisements

Question

The domain and range of real function f defined by f(x) = `sqrt(x - 1)` is given by ______.

Options

  • Domain = `(1, oo)`, Range = `(0, oo)`

  • Domain = `[1, oo)`, Range = `(0, oo)`

  • Domain = `[1, oo)`, Range = `[0, oo)`

  • Domain = `[1, oo)`, Range = `[0, oo)`

MCQ
Fill in the Blanks

Solution

The domain and range of real function f defined by f(x) = `sqrt(x - 1)` is given by Domain = `[1, oo)`, Range = `[0, oo)`.

Explanation:

Given that: f(x) = `sqrt(x - 1)`

f(x) is defined if x – 1 ≥ 0

⇒ x ≥ 1

∴ Domain of f(x) = `[0, oo)`

Let f(x) = y = `sqrt(x - 1)`

⇒ y2 = x – 1

⇒ x = y2 + 1

If x is real then y ∈ R

∴ Range of f(x) = `[0, oo)`

shaalaa.com
  Is there an error in this question or solution?
Chapter 2: Relations and Functions - Exercise [Page 31]

APPEARS IN

NCERT Exemplar Mathematics [English] Class 11
Chapter 2 Relations and Functions
Exercise | Q 32 | Page 31

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Let f be the subset of Z × Z defined by f = {(ab, a + b): a, b ∈ Z}. Is f a function from Z to Z: justify your answer.


A function f : R → R is defined by f(x) = x2. Determine (a) range of f, (b) {x : f(x) = 4}, (c) [yf(y) = −1].


Let f : R+ → R, where R+ is the set of all positive real numbers, such that f(x) = loge x. Determine

(a) the image set of the domain of f


et A = (12, 13, 14, 15, 16, 17) and f : A → Z be a function given by
f(x) = highest prime factor of x.
Find range of f.


If  \[f\left( x \right) = x^3 - \frac{1}{x^3}\] , show that

\[f\left( x \right) + f\left( \frac{1}{x} \right) = 0 .\]
 

 


If fg and h are real functions defined by 

\[f\left( x \right) = \sqrt{x + 1}, g\left( x \right) = \frac{1}{x}\] and h(x) = 2x2 − 3, find the values of (2f + g − h) (1) and (2f + g − h) (0).
 
 

If f(x) = cos [π2]x + cos [−π2x, where [x] denotes the greatest integer less than or equal to x, then write the value of f(π).


Let f : R → R be defined by f(x) = 2x + |x|. Then f(2x) + f(−x) − f(x) =


Let f(x) = x, \[g\left( x \right) = \frac{1}{x}\]  and h(x) = f(xg(x). Then, h(x) = 1


The domain of definition of the function f(x) = log |x| is


If  \[\left[ x \right]^2 - 5\left[ x \right] + 6 = 0\], where [.] denotes the greatest integer function, then 

 


Check if the following relation is function:


If f(x) = `{(x^2 + 3","  x ≤ 2),(5x + 7","  x > 2):},` then find f(0)


Check if the relation given by the equation represents y as function of x:

2x + 3y = 12


Express the area A of circle as a function of its diameter d


Express the following exponential equation in logarithmic form

e2 = 7.3890


Express the following exponential equation in logarithmic form

e–x = 6


Solve for x.

log2 + log(x + 3) – log(3x – 5) = log3


Solve for x.

x + log10 (1 + 2x) = x log10 5 + log10 6


Answer the following:

Let f : R – {2} → R be defined by f(x) = `(x^2 - 4)/(x - 2)` and g : R → R be defined by g(x) = x + 2. Examine whether f = g or not


Answer the following:

Simplify, log (log x4) – log (log x)


Answer the following:

Solve for x, logx (8x – 3) – logx 4 = 2


Answer the following:
If log3 [log2 (log3x)] = 1, show that x = 6561

The data in the adjacent table depicts the length of a person's forehand and their corresponding height. Based on this data, a student finds a relationship between the height (y) and the forehand length (x) as y = ax + b, where a, b are constant.

Length ‘x’ of
forehand (in cm)
Height 'y' 
(in inches)
35 56
45 65
50 69.5
55 74

Check if this relation is a function


Domain of function f(x) = cos–1 6x is ______.


Find the range of the following functions given by `|x - 4|/(x - 4)`


Find the range of the following functions given by `sqrt(16 - x^2)`


If f(x) = `x^3 - 1/x^3`, then `f(x) + f(1/x)` is equal to ______.


Find the domain of the following functions given by f(x) = `(x^3 - x + 3)/(x^2 - 1)`


Redefine the function f(x) = x − 2 + 2 + x , – 3 ≤ x ≤ 3


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×