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Question
Use the given figure to find:
- ∠BAD,
- ∠DQB.
Solution
i. By angle sum property of ∆ADP,
∠BAD = 180° – 85° – 40° = 55°
ii. ∠ABC = 180° – ∠ADC = 180° – 85° = 95°
(Pair of opposite angles in a cyclic quadrilateral are supplementary)
By angle sum property,
∠AQB = 180° – 95° – 55°
`=>` ∠DQB = 30°
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