Advertisements
Advertisements
प्रश्न
Differentiate the following w.r.t.x: log[tan3x.sin4x.(x2 + 7)7]
उत्तर
Let y = log[tan3x.sin4x.(x2 + 7)7]
= log tan3x + log sin4x + log(x2 + 7)7
= 3log tanx + 4log sinx + 7log(x2 + 7)
Differentiating w.r.t. x, we get
`"dy"/"dx" = "d"/"dx"[3log tanx + 4 logsinx + 7 log(x^2 + 7)]`
= `3"d"/"dx"(log tan x) + 4"d"/"dx"(log sinx) + 7"d"/"dx"[log(x^2 + 7)]`
= `3 xx (1)/tanx ."d"/"dx"(tanx) + 4 xx (1)/sinx."d"/"dx"(sinx) + 7 xx (1)/(x^2 + 7)."d"/"dx"(x^2 + 7)`
= `3 xx (1)/tanx.sec^2x + 4 xx (1)/sinx.cosx + 7 xx (1)/(x^2 + 7).(2x + 0)`
= `3 xx "cosx"/"sinx" xx (1)/(cos^2x) + 4cotx + (14x)/(x^2 + 7)`
= `(6)/(2sinx cosx) + 4cot + (14x)/(x^2 + 7)`
= `(6)/(sin2x) + 4cotx + (14x)/(x^2 + 7)`
= `6"cosec"2x + 4cotx + (14x)/(x^2 + 7)`.
APPEARS IN
संबंधित प्रश्न
Differentiate the following w.r.t.x:
`(2x^(3/2) - 3x^(4/3) - 5)^(5/2)`
Differentiate the following w.r.t.x: `(8)/(3root(3)((2x^2 - 7x - 5)^11`
Differentiate the following w.r.t.x: `sqrt(tansqrt(x)`
Differentiate the following w.r.t.x: cot3[log(x3)]
Differentiate the following w.r.t.x:
sin2x2 – cos2x2
Differentiate the following w.r.t.x: (1 + 4x)5 (3 + x −x2)8
Differentiate the following w.r.t.x: `x/(sqrt(7 - 3x)`
Differentiate the following w.r.t.x: `log(sqrt((1 - sinx)/(1 + sinx)))`
Differentiate the following w.r.t. x : tan–1(log x)
Differentiate the following w.r.t. x : cosec–1 (e–x)
Differentiate the following w.r.t. x :
`cos^-1[(3cos(e^x) + 2sin(e^x))/sqrt(13)]`
Differentiate the following w.r.t. x :
`cos^-1((1 - x^2)/(1 + x^2))`
Differentiate the following w.r.t. x :
`sin^(−1) ((1 − x^3)/(1 + x^3))`
Differentiate the following w.r.t. x : `tan^-1((8x)/(1 - 15x^2))`
Differentiate the following w.r.t.x:
`cot^-1((1 + 35x^2)/(2x))`
Differentiate the following w.r.t. x : `tan^-1((a + btanx)/(b - atanx))`
Differentiate the following w.r.t. x :
etanx + (logx)tanx
Differentiate the following w.r.t. x : `10^(x^(x)) + x^(x(10)) + x^(10x)`
Differentiate the following w.r.t. x : `[(tanx)^(tanx)]^(tanx) "at" x = pi/(4)`
Show that `"dy"/"dx" = y/x` in the following, where a and p are constants : `sec((x^5 + y^5)/(x^5 - y^5))` = a2
Show that `"dy"/"dx" = y/x` in the following, where a and p are constants : `tan^-1((3x^2 - 4y^2)/(3x^2 + 4y^2))` = a2
Show that `"dy"/"dx" = y/x` in the following, where a and p are constants: `log((x^20 - y^20)/(x^20 + y^20))` = 20
Show that `"dy"/"dx" = y/x` in the following, where a and p are constants : `sin((x^3 - y^3)/(x^3 + y^3))` = a3
If y is a function of x and log (x + y) = 2xy, then the value of y'(0) = ______.
If f(x) is odd and differentiable, then f′(x) is
If y = `"e"^(1 + logx)` then find `("d"y)/("d"x)`
If y = `sqrt(cos x + sqrt(cos x + sqrt(cos x + ...... ∞)`, show that `("d"y)/("d"x) = (sin x)/(1 - 2y)`
If y = `sin^-1[("a"cosx - "b"sinx)/sqrt("a"^2 + "b"^2)]`, then find `("d"y)/("d"x)`
If f(x) = 3x - 2 and g(x) = x2, then (fog)(x) = ________.
If x = `sqrt("a"^(sin^-1 "t")), "y" = sqrt("a"^(cos^-1 "t")), "then" "dy"/"dx"` = ______
The value of `d/(dx)[tan^-1((a - x)/(1 + ax))]` is ______.
Differentiate `tan^-1 (sqrt((3 - x)/(3 + x)))` w.r.t. x.
If y = log (sec x + tan x), find `dy/dx`.
