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प्रश्न
Evaluate : `int_-1^1 log ((2 - x)/(2 + x))dx`.
उत्तर
Let f(x) = `log((2 - x)/(2 + x))`
We have, f(– x) = `log((2 + x)/(2 - x))`
= `-log((2 - x)/(2 + x))`
= – f(x)
So, f(x) is an odd function.
∴ `int_-1^1 log ((2 - x)/(2 + x))dx` = 0.
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