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प्रश्न
Evaluate : `int 1/sqrt("x"^2 - 4"x" + 2) "dx"`
उत्तर
I = `int 1/sqrt("x"^2 - 4"x" + 2) "dx"`
`= int "dx"/sqrt("x"^2 - 4"x" +4 - 2) `
`= int "dx"/sqrt(("x - 2")^2 -( sqrt 2)^2) "dx"`
`= "log" |("x"-2) + sqrt(("x - 2")^2 -( sqrt 2)^2)| + "c"`
`= "log" |("x"-2) + sqrt("x"^2 - 4"x" + 2)| + c`
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