हिंदी

By using the properties of the definite integral, evaluate the integral: ∫0π2sin32xsin32x+cos32xdx - Mathematics

Advertisements
Advertisements

प्रश्न

By using the properties of the definite integral, evaluate the integral:

`int_0^(pi/2) sin^(3/2)x/(sin^(3/2)x + cos^(3/2) x) dx`

योग

उत्तर

Let I = `int_0^(pi/2) sin^(3/2)x/(sin^(3/2)x + cos^(3/2) x) dx`

I = `int_0^(pi/2) cos^(3/2)x/(sin^(3/2)x + cos^(3/2) x) dx`

`2I = int_0^(pi/2) (sin^(3/2)x/(sin^(3/2)x+cos^(3/2) x)+cos^(3/2)x/(sin^(3/2)x + cos^(3/2)x)) dx`

Simplify the numerator:

`(sin^(3/2)x+cos^(3/2) x)/(sin^(3/2)x+cos^(3/2)) = 1`

`2I = int_0^(pi/2) 1 dx`

`int_0^(pi/2) 1 dx = [x]_0^(pi/2)=pi/2 - 0 = pi/2`

`2I = pi/2`

`I=pi/4`

`pi/4`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Integrals - Exercise 7.11 [पृष्ठ ३४७]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 12
अध्याय 7 Integrals
Exercise 7.11 | Q 3 | पृष्ठ ३४७

संबंधित प्रश्न

If `int_0^alpha3x^2dx=8` then the value of α is :

(a) 0

(b) -2

(c) 2 

(d) ±2


Evaluate : `int e^x[(sqrt(1-x^2)sin^-1x+1)/(sqrt(1-x^2))]dx`


 
 

Evaluate `int_(-2)^2x^2/(1+5^x)dx`

 
 

If `int_0^alpha(3x^2+2x+1)dx=14` then `alpha=`

(A) 1

(B) 2

(C) –1

(D) –2


By using the properties of the definite integral, evaluate the integral:

`int_0^(pi/2)  sqrt(sinx)/(sqrt(sinx) + sqrt(cos x)) dx` 


By using the properties of the definite integral, evaluate the integral:

`int_0^(pi/4) log (1+ tan x) dx`


Evaluate the definite integrals `int_0^pi (x tan x)/(sec x + tan x)dx`


Evaluate : `int 1/("x" [("log x")^2 + 4])  "dx"`


Find `dy/dx, if y = cos^-1 ( sin 5x)`


`int_"a"^"b" "f"(x)  "d"x` = ______


State whether the following statement is True or False:

`int_(-5)^5 x/(x^2 + 7)  "d"x` = 10


`int_0^(pi/4) (sec^2 x)/((1 + tan x)(2 + tan x))`dx = ?


The value of `int_-3^3 ("a"x^5 + "b"x^3 + "c"x + "k")"dx"`, where a, b, c, k are constants, depends only on ______.


`int_0^4 1/(1 + sqrtx)`dx = ______.


`int_"a"^"b" sqrtx/(sqrtx + sqrt("a" + "b" - x)) "dx"` = ______.


`int_0^1 (1 - x)^5`dx = ______.


`int_0^{pi/2} cos^2x  dx` = ______ 


`int_0^{1/sqrt2} (sin^-1x)/(1 - x^2)^{3/2} dx` = ______ 


`int_-1^1x^2/(1+x^2)  dx=` ______.


`int_(-1)^1 (x^3 + |x| + 1)/(x^2 + 2|x| + 1) "d"x` is equal to ______.


If `int_0^1 "e"^"t"/(1 + "t") "dt"` = a, then `int_0^1 "e"^"t"/(1 + "t")^2 "dt"` is equal to ______.


`int_0^(2"a") "f"(x) "d"x = 2int_0^"a" "f"(x) "d"x`, if f(2a – x) = ______.


`int_0^(pi/2) sqrt(1 - sin2x)  "d"x` is equal to ______.


If `int (log "x")^2/"x" "dx" = (log "x")^"k"/"k" + "c"`, then the value of k is:


`int_a^b f(x)dx = int_a^b f(x - a - b)dx`.


If `int_0^1(sqrt(2x) - sqrt(2x - x^2))dx = int_0^1(1 - sqrt(1 - y^2) - y^2/2)dy + int_1^2(2 - y^2/2)dy` + I then I equal.


If `β + 2int_0^1x^2e^(-x^2)dx = int_0^1e^(-x^2)dx`, then the value of β is ______.


Let f be continuous periodic function with period 3, such that `int_0^3f(x)dx` = 1. Then the value of `int_-4^8f(2x)dx` is ______.


Evaluate: `int_0^π x/(1 + sinx)dx`.


For any integer n, the value of `int_-π^π e^(cos^2x) sin^3 (2n + 1)x  dx` is ______.


Evaluate: `int_0^(π/4) log(1 + tanx)dx`.


If `int_0^1(3x^2 + 2x+a)dx = 0,` then a = ______


Evaluate the following definite integral:

`int_-2^3 1/(x + 5) dx`


Evaluate the following integral:

`int_-9^9x^3/(4-x^2)dx`


Solve.

`int_0^1e^(x^2)x^3dx`


Solve the following.

`int_0^1e^(x^2)x^3dx`


Evaluate the following definite intergral:

`int_1^2 (3x)/(9x^2 - 1) dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×