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प्रश्न
Evaluate the following:
`Γ (9/2)`
योग
उत्तर
`Γ (9/2) = (9 /2 - 1) Γ(9/2 - 1)`
= `7/2 Γ 7/2`
= `7/2 5/2 Γ 5/2`
= `7/2 5/2 3/2 Γ 3/2`
= `7/2 5/2 3/2 1/2 Γ (1/2)`
= `(105sqrt(pi))/16`
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Definite Integrals
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Integral Calculus – 1 - Exercise 2.10 [पृष्ठ ५१]
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