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प्रश्न
Find the principal value of `cot^(-1) (sqrt3)`
उत्तर
Let `cot^(-1)(sqrt3) = y` Then `cot y = sqrt3 = cot (pi/6)`
We know that the range of the principal value branch of cot−1 is (0,π)
`"Then"cot (pi/6) = sqrt3`
Where `pi/6 ∈ (0, pi)`
Therefore, the principal value of `cot^(-1) (sqrt3) " is " pi/6.`
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