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Find the range of the following functions given by f(x) = 32-x2 - Mathematics

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प्रश्न

Find the range of the following functions given by f(x) = `3/(2 - x^2)`

योग

उत्तर

Let f(x) = y

y = `3/(2 - x^2)`

⇒ 2 – x2

= `3/"y"`

⇒ = `2 - 3/y`

But, we know that, x2 ≥ 0

`2 - 3/y ≥ 0`

⇒ `(2y - 3)/y ≥ 0`

⇒ y > 0 and 2y – 3 ≥ 0

⇒ y > 0 and 2y ≥ 3

⇒ y > 0 and y ≥ `3/2`

Or f(x) > 0 and f(x) ≥ `3/2`

 f(x) ∈ `( – oo, 0) ∪ (3/2 , oo)`

⇒ f(x) ∈ `( – oo, 0) ∪ (3/2 , oo)`

Therefore, the range of f = `(-oo, 0) ∪ (3/2 , oo)`.

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अध्याय 2: Relations and Functions - Exercise [पृष्ठ २९]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 2 Relations and Functions
Exercise | Q 18.(i) | पृष्ठ २९

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