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प्रश्न
If 0° < A < 90°; find A, if `sinA/(secA - 1) + sinA/(secA + 1) = 2`
उत्तर
`sinA/(secA - 1) + sinA/(secA + 1) = 2`
`=> (sinAsecA + sinA + secAsinA - sinA)/((secA - 1)(secA + 1)) = 2`
`=> (2sinAsecA)/(sec^2A - 1) = 2`
`=> (sinAsecA)/tan^2A = 1`
`=> cosA/sinA = 1`
`=>` cot A = 1
We know cot 45° = 1
Hence, A = 45°
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