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प्रश्न
If sin 3A = cos 6A, then ∠A = ?
उत्तर
sin 3A = cos 6A .....[Given]
∴ sin 3A = sin(90° – 6A) .....[∵ cos θ = sin(90° – θ)]
∴ 3A = 90° – 6A
∴ 3A + 6A = 90°
∴ 9A = 90°
∴ A = `(90^circ)/9`
∴ A = 10°
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