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प्रश्न
If x = `2sqrt3 + 2sqrt2`, find: `1/x`
उत्तर
`1/x = 1/[2sqrt3 + 2sqrt2] xx [2sqrt3 - 2sqrt2]/[2sqrt3 - 2sqrt2]`
= `[2sqrt3 - 2sqrt2]/[(2sqrt3)^2 - (2sqrt2)^2]`
= `[2sqrt3 - 2sqrt2]/(12 - 8)`
= `[cancel(2)^1(sqrt3 - sqrt2)]/cancel(4)_2`
= `(sqrt3 - sqrt2)/2`
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