Advertisements
Advertisements
प्रश्न
In ∆ABC, P and Q are points on sides AB and AC respectively such that PQ || BC. If AP = 3 cm, PB = 5 cm and AC = 8 cm, find AQ.
उत्तर
In Δ ABC, P and Q are points on sides AB and AC respectively such that `PQ|| BC`
Then we have
`(AP)/(AB)=(AQ)/(AC)`
AP = 3cm ,PB = 5cm ,AC = 8cm and AB = cm
`3/8=(AQ)/8`
`3/cancel8=(AQ)/cancel8`
`3= AQ`
Hence the value of AQ is 3 cm.
APPEARS IN
संबंधित प्रश्न
In ∆ABC, AD and BE are altitude. Prove that\[\frac{ar\left( ∆ DEC \right)}{ar\left( ∆ ABC \right)} = \frac{{DC}^2}{{AC}^2}\]
In ∆ABC, ∠A = 60°. Prove that BC2 = AB2 + AC2 − AB . AC.
In the figure given below DE || BC. If AD = 2.4 cm, DB = 3.6 cm, AC = 5 cm. Find AE.
In the given figure, DE || BC in ∆ABC such that BC = 8 cm, AB = 6 cm and DA = 1.5 cm. Find DE.
XY is drawn parallel to the base BC of a ∆ABC cutting AB at X and AC at Y. If AB = 4 BX and YC = 2 cm, then AY =
A vertical stick 20 m long casts a shadow 10 m long on the ground. At the same time, a tower casts a shadow 50 m long on the ground. The height of the tower is
∆ABC is a right triangle right-angled at A and AD ⊥ BC. Then, \[\frac{BD}{DC} =\]
In a right triangle ABC right-angled at B, if P and Q are points on the sides AB and AC respectively, then
If ∆ABC ∼ ∆DEF such that DE = 3 cm, EF = 2 cm, DF = 2.5 cm, BC = 4 cm, then perimeter of ∆ABC is
In the given figure, Δ AHK ∼ Δ ABC. If AK = 8 cm, BC = 3.2 cm and HK = 6.4 cm, then find the length of AC.