Advertisements
Advertisements
प्रश्न
In the given figure, O and O' are centres of two circles intersecting at B and C. ACD is a straight line, find x.
उत्तर
It is given that
Two circles having center O and O' and ∠AOB = 130°
And AC is diameter of circle having center O
We have
`angle ACB =1/2 angleAOB = 65°`
So
`angleDCB = 180° - angleACB`
= 180° - 65°
= 115°
Now, reflex `angleBO'D = 2 angleBCD`
So
`360° - x° = 2 xx 115 `
= 230°
APPEARS IN
संबंधित प्रश्न
Prove that the line joining the mid-point of a chord to the centre of the circle passes through the mid-point of the corresponding minor arc.
If O is the centre of the circle, find the value of x in the following figure:
If O is the centre of the circle, find the value of x in the following figure
Prove that the angle in a segment shorter than a semicircle is greater than a right angle.
In the given figure, A is the centre of the circle. ABCD is a parallelogram and CDE is a straight line. Find ∠BCD : ∠ABE.
In the given figure, AB is a diameter of the circle such that ∠A = 35° and ∠Q = 25°, find ∠PBR.
In the given figure, P and Q are centres of two circles intersecting at B and C. ACD is a straight line. Then, ∠BQD =
If arcs AXB and CYD of a circle are congruent, find the ratio of AB and CD.
A chord of a circle is equal to its radius. Find the angle subtended by this chord at a point in major segment.
A circle has radius `sqrt(2)` cm. It is divided into two segments by a chord of length 2 cm. Prove that the angle subtended by the chord at a point in major segment is 45°.
