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Prove that: cos2θ (1 + tan2θ) - Geometry Mathematics 2

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प्रश्न

Prove that:

cos2θ (1 + tan2θ)

योग

उत्तर

L.H.S. = cos2θ (1 + tan2θ)

= cos2θ × sec2θ          ...[∵ 1 + tan2 θ = sec2 θ]

= \[\cos^{2}\theta\times\frac{1}{\cos^{2}\theta}\]

= 1

= R.H.S.

∴ cos2θ (1 + tan2θ) = 1

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Application of Trigonometry
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Trigonometry - Practice Set 6.1 [पृष्ठ १३१]

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बालभारती Geometry (Mathematics 2) [English] 10 Standard SSC Maharashtra State Board
अध्याय 6 Trigonometry
Practice Set 6.1 | Q 6.02 | पृष्ठ १३१
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