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प्रश्न
Prove that:
`(sin^2θ)/(cosθ) + cosθ = secθ`
उत्तर
LHS = `(sin^2θ)/(cosθ) + cosθ = secθ`
= `(sin^2θ + cos^2θ)/(cosθ)`
= `1/(cosθ)` ...(sin2θ + cos2θ = 1)
= secθ ...`(1/cosθ = secθ)`
R.H.S
LHS = RHS
Hence proved.
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