Advertisements
Advertisements
प्रश्न
The quadrilateral formed by angle bisectors of a cyclic quadrilateral is also cyclic. Prove it.
उत्तर
Given – ABCD is a cyclic quadrilateral and PQRS is a quadrilateral formed by the angle bisectors of angle ∠A, ∠B, ∠C and ∠D
To prove – PQRS is a cyclic quadrilateral.
Proof – In ΔAPD,
∠PAD + ∠ADP + ∠APD = 180° ...(1)
Similarly, In ∆BQC,
∠QBC + ∠BCQ + ∠BQC = 180° ...(2)
Adding (1) and (2), we get
∠PAD + ∠ADP + ∠APD + ∠QBC + ∠BCQ + ∠BQC = 180° + 180°
`=>` ∠PAD + ∠ADP + ∠QBC + ∠BCQ + ∠APD + ∠BQC = 360°
But ∠PAD + ∠ADP + ∠QBC + ∠BCQ
= `1/2` [∠A + ∠B + ∠C + ∠D]
= `1/2 xx 360^circ`
= 180°
∴ ∠APD + ∠BQC = 360° – 180° = 180° ...[From (3)]
But these are the sum of opposite angles of quadrilateral PRQS.
∴ Quad. PRQS is a cyclic quadrilateral.
APPEARS IN
संबंधित प्रश्न
ABCD is a cyclic quadrilateral in a circle with centre O. If ∠ADC = 130°; find ∠BAC.
In the figure, ABCD is a cyclic quadrilateral with BC = CD. TC is tangent to the circle at point C and DC is produced to point G. If ∠BCG = 108° and O is the centre of the circle, find :
- angle BCT
- angle DOC
In the given figure, C and D are points on the semi-circle described on AB as diameter. Given angle BAD = 70° and angle DBC = 30°, calculate angle BDC.
In a cyclic quadrilateral ABCD, ∠A : ∠C = 3 : 1 and ∠B : ∠D = 1 : 5; find each angle of the quadrilateral.
In the given figure, PAT is tangent to the circle with centre O at point A on its circumference and is parallel to chord BC. If CDQ is a line segment, show that:
- ∠BAP = ∠ADQ
- ∠AOB = 2∠ADQ
- ∠ADQ = ∠ADB
Two circles intersect in points P and Q. A secant passing through P intersects the circles in A and B respectively. Tangents to the circles at A and B intersect at T. Prove that A, Q, B and T lie on a circle.
In a cyclic quadrilateral ABCD , AB || CD and ∠ B = 65° , find the remaining angles.
In the figure, ∠DBC = 58°. BD is a diameter of the circle. Calculate : ∠BEC
ABCD is a cyclic quadrilateral AB and DC are produced to meet in E. Prove that Δ EBC ∼ Δ EDA.
The diagonals of a cyclic quadrilateral are at right angles. Prove that the perpendicular from the point of their intersection on any side when produced backward bisects the opposite side.