हिंदी

Using the Method of Integration, Find the Area of the Triangle Abc, Coordinates of Whose Vertices Are a (4 , 1), B (6, 6) and C (8, 4). - Mathematics

Advertisements
Advertisements

प्रश्न

Using the method of integration, find the area of the triangle ABC, coordinates of whose vertices are A (4 , 1), B (6, 6) and C (8, 4).

उत्तर

Equation of AB

`y - y_1 = (y_2 -y_1)/(x_2-x_1) (x - x_1)`

`y - 1 = (6-1)/(6-4) (x - 4)`

`y - 1 = 5/2 (x - 4)`

2y - 2 = 5x - 20

`y = (5x)/2 - 9`

Equation of BC

`y - 6 = (4 - 6)/(8 - 6) (x - 6)`

`y - 6 = (-2)/(+2) (x - 6)`

y - 6 = -x + 6

y = -x + 12

Equation of AC

`y - 1 = (4 -1)/(8 - 4) (x - 4)`

`y -1 = 3/4 (x - 4)`

`4y - 4 = 3x - 12`

`y = (3x)/4 - 2`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2016-2017 (March) All India Set 1

वीडियो ट्यूटोरियलVIEW ALL [3]

संबंधित प्रश्न

Area lying in the first quadrant and bounded by the circle x2 + y2 = 4 and the lines x = 0 and x = 2 is ______.


Find the area enclosed by the parabola 4y = 3x2 and the line 2y = 3x + 12


Find the area enclosed between the parabola 4y = 3x2 and the straight line 3x - 2y + 12 = 0.


Find the equation of an ellipse whose latus rectum is 8 and eccentricity is `1/3`


Using integration, find the area of the region {(x, y) : x2 + y2 ≤ 1 ≤ x + y}.


Find the area of the region. 

{(x,y) : 0 ≤ y ≤ x, 0 ≤ y ≤ x + 2 ,-1 ≤ x ≤ 3} .


The area of the region bounded by y2 = 4x, the X-axis and the lines x = 1 and x = 4 is _______.


Area of the region bounded by x2 = 16y, y = 1 and y = 4 and the Y-axis, lying in the first quadrant is _______.


Solve the following :

Find the area of the region bounded by the curve xy = c2, the X-axis, and the lines x = c, x = 2c.


Solve the following :

Find the area of the region bounded by the curve y = x2 and the line y = 10.


Choose the correct alternative:

Area of the region bounded by the curve y = x3, x = 1, x = 4 and the X-axis is ______


Choose the correct alternative:

Area of the region bounded by x = y4, y = 1 and y = 5 and the Y-axis lying in the first quadrant is ______


State whether the following statement is True or False:

The equation of the area of the circle is `x^2/"a"^2 + y^2/"b"^2` = 1


The area of the region bounded by the curve y2 = 4x, the X axis and the lines x = 1 and x = 4 is ______


The area of the region lying in the first quadrant and bounded by the curve y = 4x2, and the lines y = 2 and y = 4 is ______


Find the area of the region bounded by the curve y = (x2 + 2)2, the X-axis and the lines x = 1 and x = 3


Find area of the region bounded by the parabola x2 = 36y, y = 1 and y = 4, and the positive Y-axis


Find the area of the region bounded by the curve y = `sqrt(36 - x^2)`, the X-axis lying in the first quadrant and the lines x = 0 and x = 6


Find the area of the circle x2 + y2 = 62 


The area bounded by y = `27/x^3`, X-axis and the ordinates x = 1, x = 3 is ______


Area bounded by the curve xy = 4, X-axis between x = 1, x = 5 is ______.


Area under the curve `y=sqrt(4x+1)` between x = 0 and x = 2 is ______.


The area enclosed by the parabolas x = y2 - 1 and x = 1 - y2 is ______.


The area of the region bounded by the curve y = x IxI, X-axis and the ordinates x = 2, x = –2 is ______.


The area included between the parabolas y2 = 4a(x +a) and y2 = 4b(x – a), b > a > 0, is


The slope of a tangent to the curve y = 3x2 – x + 1 at (1, 3) is ______.


The area of the region bounded by the curve y = x2, x = 0, x = 3, and the X-axis is ______.


The area (in sq.units) of the part of the circle x2 + y2 = 36, which is outside the parabola y2 = 9x, is ______.


If the area enclosed by y = f(x), X-axis, x = a, x = b and y = g(x), X-axis, x = a, x = b are equal, then f(x) = g(x).


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×