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प्रश्न
A man goes 10 m due east and then 24 m due north. Find the distance from the straight point.
उत्तर
Let O be the original position of the man.
From the figure, it is clear that B is the final position of the man.
ΔAOB is right-angled at A.
By Pythagoras theorem,
OB2 = OA2 + AB2
OB2 = (10m)2 + (24m)2
OB2 = 100m2 + 576m2
OB2 = 676m2
OB2 = (26m)2
OB = 26m
Thus, the man is at a distance of 26m from the straight point.
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