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प्रश्न
Evaluate the following:
`int_0^oo "e"^(-4x) x^4 "d"x`
बेरीज
उत्तर
`int_0^oo "e"^(-4x) x^4 "d"x = int_0^oo x^"n" "e"^(-ax) "d"x`
`("n"!)/("a"^("n" + 1))`
Where n = 4
a = 4
So the integral becomes `(4!)/4^5 = (4 xx 3 xx 2)/(4 xx 4 xx 4 xx 4 xx 4)`
= `3/128`
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Definite Integrals
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2: Integral Calculus – 1 - Exercise 2.10 [पृष्ठ ५१]
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