Advertisements
Advertisements
प्रश्न
f X − Y =`[[1 1 1],[1 1 0],[1 0 0]]` and X + Y = `[[3 5 1],[-1 1 1],[11 8 0]]`find X and Y.
उत्तर
Here,
X−Y+X+Y= `[[1,1,1],[1,1,0],[1,0,0]]+` `[[3,5,1],[-1,1,4],[11,8,0]]`
`⇒ 2X= [[1+3,1+5,1+1],[1-1,1+1 ,0+1 ],[1+11,0+8,0+0]]`
`⇒ 2X =[[4,6 ,2],[0,2,4],[12,8,0]]`
`⇒ X = 1/2 [[4 6 2],[0 2 4],[12 8 0]]`
`⇒ X=[[2 3 1],[0 1 2],[6 4 0]]`
Now,
`(X-Y)-(X+Y)=[[1 1 1],[1 1 0],[1 0 0]]`-`[[3 5 1],[-1 1 1],[11 8 0]]`
⇒X−Y−X−Y=`[[1-3 1-5 1-1 ],[1+1 1-1 0-4],[1-11 0-8 0-0]]`
⇒−2Y= `[[-2 -4 0],[2 0 -4],[-10 -8 0]]`
⇒Y=−`1/2` `[[-2 -4 0],[2 0 -4],[-10 -8 0]]`
⇒Y=`[[1 2 0],[-1 0 2],[5 4 0]]`
`∴ X= [[2 3 1],[0 1 2],[6 4 0]]` And Y = `=[[1 2 0],[-1 0 2],[5 4 0]]`
APPEARS IN
संबंधित प्रश्न
Solve the following matrix equation for x: `[x 1] [[1,0],[−2,0]]=0`
If A = `([cos alpha, sin alpha],[-sinalpha, cos alpha])` , find α satisfying 0 < α < `pi/r`when `A+A^T=sqrt2I_2` where AT is transpose of A.
If `A=[[1,2,2],[2,1,2],[2,2,1]]` ,then show that `A^2-4A-5I=0` and hence find A-1.
Compute the following:
`[(a^2+b^2, b^2+c^2),(a^2+c^2, a^2+b^2)] + [(2ab , 2bc),(-2ac, -2ab)]`
Compute the following:
`[(cos^2x, sin^2 x),(sin^2 x ,cos^2 x)]+[(sin^2 x, cos^2 x), (cos^2 x, sin^2 x)]`
If F(x) = `[(cosx, -sinx,0), (sinx, cosx, 0),(0,0,1)]` show that F(x)F(y) = F(x + y)
Compute the following sums:
`[[2 1 3],[0 3 5],[-1 2 5]]`+ `[[1 -2 3],[2 6 1],[0 -3 1]]`
Let A = `[[2,4],[3,2]]`, `B=[[1,3],[-2,5]]`and `c =[[-2,5],[3,4]]`.Find each of the following: 3A − C
If A =`[[2,3],[5,7]],B =` `[[-1,0 ,2],[3,4,1]]`,`C= [[-1,2,3],[2,1,0]]`find : A + B and B + C
If A =`[[2 3],[5 7]],B =` `[[-1 0 2],[3 4 1]]`,`C= [[-1 2 3],[2 1 0]]`find
2B + 3A and 3C − 4B
If A = diag (2 − 59), B = diag (11 − 4) and C = diag (−6 3 4), find
B + C − 2A
If A = diag (2 − 59), B = diag (11 − 4) and C = diag (−6 3 4), find
2A + 3B − 5C
Find matrices X and Y, if 2X − Y = `[[6 -6 0],[-4 2 1]]`and X + 2Y =`[[3 2 5],[-2 1 -7 ]]`
If A = `[[1 -3 2],[2 0 2]]`and `B = [[2 -1 -1],[1 0 -1]]` find the matrix C such that A + B + C is
, find the matrix C such that A + B + C is zero matrix.
Find x, y satisfying the matrix equations
`[[X-Y 2 -2],[4 x 6]]+[[3 -2 2],[1 0 -1]]=[[ 6 0 0],[ 5 2x+y 5]]`
Find x, y satisfying the matrix equations
`[x y + 2 z-3 ] + [ y 4 5]=[4 9 12]`
Find x, y satisfying the matrix equations
`x[[2],[1]]+y[[3],[5]]+[[-8],[-11]]=0`
Find the value of λ, a non-zero scalar, if λ
Find a matrix X such that 2A + B + X = O, where
`A= [[-1 2],[3 4]],B= [[3 -2],[1 5]]`
Find a matrix X such that 2A + B + X = O, where
If A = `[[8 0],[4 -2],[3 6]]` and B = `[[2 -2],[4 2],[-5 1]]`
, then find the matrix X of order 3 × 2 such that 2A + 3X = 5B.
Find x, y, z and t, if
`2[[x 5],[z t]]+[[x 6],[-1 2t]]=[[7 14],[15 14]]`
If X and Y are 2 × 2 matrices, then solve the following matrix equations for X and Y.
`2X + 3Y = [[2,3],[4,0]], 3X+2Y = [[-2,2],[1,-5]]`
Express the matrix \[A = \begin{bmatrix}3 & - 4 \\ 1 & - 1\end{bmatrix}\] as the sum of a symmetric and a skew-symmetric matrix.
If \[\binom{x + y}{x - y} = \begin{bmatrix}2 & 1 \\ 4 & 3\end{bmatrix}\binom{1}{ - 2}\] , then write the value of (x, y).
If \[I = \begin{bmatrix}1 & 0 \\ 0 & 1\end{bmatrix}, J = \begin{bmatrix}0 & 1 \\ - 1 & 0\end{bmatrix} and B = \begin{bmatrix}\cos \theta & \sin \theta \\ - \sin \theta & \cos \theta\end{bmatrix}\] then B equals )
The trace of the matrix \[A = \begin{bmatrix}1 & - 5 & 7 \\ 0 & 7 & 9 \\ 11 & 8 & 9\end{bmatrix}\], is
If possible, find the sum of the matrices A and B, where A = `[(sqrt(3), 1),(2, 3)]`, and B = `[(x, y, z),(a, "b", 6)]`
If A = `[(2, 1)]`, B = `[(5, 3, 4),(8, 7, 6)]` and C = `[(-1, 2, 1),(1, 0, 2)]`, verify that A(B + C) = (AB + AC).
Let A = `[(1, 2),(-1, 3)]`, B = `[(4, 0),(1, 5)]`, C = `[(2, 0),(1, -2)]` and a = 4, b = –2. Show that: (a + b)B = aB + bB
If A = `[(1, 2),(4, 1)]`, find A2 + 2A + 7I.
`"A" = [(1,-1),(2,-1)], "B" = [("x", 1),("y", -1)]` and (A + B)2 = A2 + B2, then x + y = ____________.
If a2 + b2 + c2 = –2 and f(x) = `|(1 + a^2x, (1 + b^2)x, (1 + c^2)x),((1 + a^2)x, 1 + b^2x, (1 + c^2)x),((1 + a^2)x, (1 + b^2)x, (1 + c^2)x)|` then f(x) is a polynomial of degree ______.
