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तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएस.एस.एल.सी. (इंग्रजी माध्यम) इयत्ता ९

Find the value of the following: cotθtan(90∘-θ)+cos(90∘-θ)tanθsec(90∘-θ)sin(90∘-θ)cot(90∘-θ)cosec(90∘-θ) - Mathematics

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प्रश्न

Find the value of the following:

`cot theta/(tan(90^circ - theta)) + (cos(90^circ - theta) tantheta sec(90^circ - theta))/(sin(90^circ - theta)cot(90^circ - theta)"cosec"(90^circ - theta))`

बेरीज

उत्तर

`cot theta/(tan(90^circ - theta)) + (cos(90^circ - theta) tantheta sec(90^circ - theta))/(sin(90^circ - theta)cot(90^circ - theta)"cosec"(90^circ - theta))`

= `cot theta/cot theta + (sin theta* tan theta xx "cosec" theta)/(cos theta xx tan theta * sec theta)`

= `1 + sin theta/cos theta xx 1/sintheta xx costheta/1`

= 1 + 1

= 2

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पाठ 6: Trigonometry - Exercise 6.3 [पृष्ठ २३५]

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सामाचीर कलवी Mathematics [English] Class 9 TN Board
पाठ 6 Trigonometry
Exercise 6.3 | Q 1. (iv) | पृष्ठ २३५
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