मराठी
महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

If cot( 90 – A ) = 1, then ∠A = ? - Geometry Mathematics 2

Advertisements
Advertisements

प्रश्न

If cot( 90 – A ) = 1, then ∠A = ?

बेरीज

उत्तर

cot(90 – A) = 1     .....[Given]

∴ tan A = 1

∴ A = 45°    .....[∵ tan 45° = 1]

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 6: Trigonometry - Q.1 (B)

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

Without using trigonometric tables, evaluate the following:

`(\sin ^{2}20^\text{o}+\sin^{2}70^\text{o})/(\cos ^{2}20^\text{o}+\cos ^{2}70^\text{o}}+\frac{\sin (90^\text{o}-\theta )\sin \theta }{\tan \theta }+\frac{\cos (90^\text{o}-\theta )\cos \theta }{\cot \theta }`


If tan 2θ = cot (θ + 6º), where 2θ and θ + 6º are acute angles, find the value of θ


What is the value of (cos2 67° – sin2 23°)?


Prove the following trigonometric identities.

(cosecA − sinA) (secA − cosA) (tanA + cotA) = 1


if `3 cos theta = 1`, find the value of `(6 sin^2 theta + tan^2 theta)/(4 cos theta)`


if `sqrt3 tan theta = 3 sin theta` find the value of `sin^2 theta - cos^2 theta`


Show that : `sin26^circ/sec64^circ  + cos26^circ/(cosec64^circ) = 1`


Find the value of x, if tan x = `(tan60^circ - tan30^circ)/(1 + tan60^circ tan30^circ)`


Use tables to find cosine of 26° 32’


Use tables to find the acute angle θ, if the value of cos θ is 0.6885


Evaluate:

`sec26^@ sin64^@ + (cosec33^@)/sec57^@`


Evaluate:

`(cos75^@)/(sin15^@) + (sin12^@)/(cos78^@) - (cos18^@)/(sin72^@)`


Prove that:

sec (70° – θ) = cosec (20° + θ)


If the angle θ = –45° , find the value of tan θ.


If tan2 45° − cos2 30° = x sin 45° cos 45°, then x


The value of

\[\frac{\cos \left( 90°- \theta \right) \sec \left( 90°- \theta \right) \tan \theta}{cosec \left( 90°- \theta \right) \sin \left( 90° - \theta \right) \cot \left( 90°- \theta \right)} + \frac{\tan \left( 90° - \theta \right)}{\cot \theta}\] 

 


Sin 2A = 2 sin A is true when A =


Prove that:
(sin θ + 1 + cos θ) (sin θ − 1 + cos θ) . sec θ cosec θ = 2


Evaluate: `2(tan57°)/(cot33°) - (cot70°)/(tan20°) - sqrt(2) cos 45°`


The value of the expression (cos2 23° – sin2 67°) is positive.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×