Advertisements
Advertisements
प्रश्न
In triangle ABC, AB = AC = 15 cm and BC = 18 cm, find cos ∠ABC.
उत्तर
Consider the figure below :
In the isosceles ΔABC, AB = AC = 15cm and BC =18cm the perpendicular drawn from angle A to the side BC divides the side BC into two equal parts BD = DC = 9 cm
cos ∠ABC = `"base"/"hypotenuse" = "BD"/"AB" = (9)/(15) = (3)/(5)`
APPEARS IN
संबंधित प्रश्न
In Fig below, Find tan P and cot R. Is tan P = cot R?
If ∠A and ∠P are acute angles such that tan A = tan P, then show that ∠A = ∠P.
In right angled triangle ΔABC at B, ∠A = ∠C. Find the values of sin A sin B + cos A cos B
If sin 3θ = cos (θ – 6°) where 3θ and θ − 6° are acute angles, find the value of θ.
In a ΔABC , ∠B = 90° , AB= 24 cm and BC = 7 cm find (i) sin A (ii) cos A (iii) sin C (iv) cos C
Evaluate:
cos450 cos300 + sin450 sin300
Form the following figure, find the values of:
- cos B
- tan C
- sin2B + cos2B
- sin B. cos C + cos B. sin C
If tan x = `1(1)/(3)`, find the value of : 4 sin2x - 3 cos2x + 2
If sinA = 0.8, find the other trigonometric ratios for A.
In an isosceles triangle ABC, AB = BC = 6 cm and ∠B = 90°. Find the values of cos C
