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प्रश्न
उत्तर
\[\int\frac{\log x}{x}dx\]
\[Let, \log x = t\]
\[ \Rightarrow \frac{1}{x} = \frac{dt}{dx}\]
\[Now, \int\frac{\log x}{x}dx\]
= ∫ t . dt
\[ = \frac{t^2}{2} + C\]
\[ = \frac{\left( \log x \right)^2}{2} + C\]
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